(4)(k^2+k-42)=0

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Solution for (4)(k^2+k-42)=0 equation:


Simplifying
(4)(k2 + k + -42) = 0

Reorder the terms:
4(-42 + k + k2) = 0
(-42 * 4 + k * 4 + k2 * 4) = 0
(-168 + 4k + 4k2) = 0

Solving
-168 + 4k + 4k2 = 0

Solving for variable 'k'.

Factor out the Greatest Common Factor (GCF), '4'.
4(-42 + k + k2) = 0

Factor a trinomial.
4((-7 + -1k)(6 + -1k)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-7 + -1k)' equal to zero and attempt to solve: Simplifying -7 + -1k = 0 Solving -7 + -1k = 0 Move all terms containing k to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1k = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1k = 0 + 7 -1k = 0 + 7 Combine like terms: 0 + 7 = 7 -1k = 7 Divide each side by '-1'. k = -7 Simplifying k = -7

Subproblem 2

Set the factor '(6 + -1k)' equal to zero and attempt to solve: Simplifying 6 + -1k = 0 Solving 6 + -1k = 0 Move all terms containing k to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + -1k = 0 + -6 Combine like terms: 6 + -6 = 0 0 + -1k = 0 + -6 -1k = 0 + -6 Combine like terms: 0 + -6 = -6 -1k = -6 Divide each side by '-1'. k = 6 Simplifying k = 6

Solution

k = {-7, 6}

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